LC3 Assembly language :: Assembly

LC3 Assembly language

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I'm very new to the assembly language and in class we're working on a division program using the LC3 simulator. Below is my code for my division algorithm.

DIVISION: AND R3, R3, 0 ; Zero out R3 /This is the remainder AND R4, R4, 0 ; Zero out R4 /This is the quotient NOT R3, R2 ; Takes the inverse of 2nd input ->R3 ADD R3, R3 #1 ; Add one to the inverse (for 2s comp) LOOPD ADD R4, R4, #1 ; Add 1 to R4 repeatedly ADD R1, R1, R3 ; Subtract input2 from R1 BRN NEGATIVE BRZ ZERO BRP LOOPD NEGATIVE ADD R4, R4, #-1 ADD R3, R1, R2 ; Done with divison algorithm. ZERO LD R0, DECCONV ; Load Decimal converter ADD R3, R3, R0 ; Convert back to ASCII ADD R4, R4, R0 ; Convert back to ASCII ST R3, REMRESULT ; Store the remainder result ST R4, DIVRESULT ; Store the division result. LD R0, DIVRESULT ; Load Division result into R0 PUTC ; Print it. LEA R0, DIVSTRING ; Load the string for division. PUTS ; Print the string. LD R0, REMRESULT ; Load Remainder result into R0 PUTC ; Print it. LEA R0, REMSTRING ; Load the string for remainder PUTS ; Print the string.

When I enter two inputs, for example: 4 and 2. I get 2 for the quotient and 1 for the remainder. When I enter 9, 3 I get 6 remainder 1..

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